During an electrolysis of conc H 2 S O 4 , peroxydisulphuric acid H 2 S 2 O 8 and O 2 form in an equimolar amount. The moles of H 2 that will be formed simultaneously will be

Step-by-step solution

2 H 2 O → O 2 + 4 H + + 4 e - 2 S O 4 2 - → S 2 O 8 2 - + 2 e - For 1 mole each of O 2 and S 2 O 8 2 - , no of mole of e - = 6 mole e - So 6 mole e - 6 H + + 6 e - → 3 H 2 Hence it produces 3 moles H 2