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Resistance of a 0.1 M K C l solution in a conductance cell is 300 o h m and specific conductance of 0.1 M K C l is 1.33 × 1 0 - 2 o h m - 1 c m - 1 . The resistance of 0.1 M N a C l solution in the same cell is 400 ohm . The equivalent conductance of the 0.1 M N a C l solution (in o h m - 1 c m 2 / g m e q . ) is

Correct answer

100

Step-by-step solution

κ = 1 R l A i.e. l A = R × κ = 300 × 1.33 × 1 0 - 2 ≃ 4.0 c m - 1 κ N a C l = 1 R l A = 1 400 × 4.0 Λ m ( NaCl ⁡ ) = κ × 1000 M = 4.0 400 × 1000 0.1 = 100

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