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The voltage of the cell consisting of L i s and F 2 g electrodes is 5.92 V at standard condition at 298 K. What is the voltage if the electrolyte consists of 2 M LiF. (ln2 = 0.693, R = 8.314 J K - 1 m o l - 1 and F = 96500 C m o l - 1 )

Options

  1. A5.90 V
  2. B5.937 V
  3. C5.88 V
  4. D4.9 V

Correct answer

A. 5.90 V

Step-by-step solution

2 L i s + F 2 g → 2 L i F a q E c e l l o = 5.92 V E c e l l = E c e l l o - 0.0591 2 l o g [ L i F ] 2 E c e l l = 5.92 - 0.059 2 l o g 2 2 = 5.92 - 0.059 × 0.3010 = 5.90 V

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