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When an electric current is passed through acidulated, water, 112 mL of hydrogen gas at NTP collects at the cathode in 965 seconds. The current passed, in amperes, is

Correct answer

1

Step-by-step solution

22,400 mL of hydrogen at STP (or NTP) = 2g So 112 mL of hydrogen at STP = 2 g × 112 m L 22,400 m L = 1 0 - 2 g 2 H + + 2 e - 2 F → H 2 1 mol = 2 × 96500 C = 2 g 2 g hydrogen is deposited by = 2 × 96500 C So 1 0 - 2 g hydrogen will be deposited by = 2 × 96500 × 1 0 - 2 g 2 g = 965 C Charge Q = i t So i = Q t = 965 C 965 s = 1 C s - 1 = 1 A

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