NTA Abhyas JEE Main2020ChemistryElectrochemistryPractice
At p H = 2 , E Q u i n h y d r o n e 0 = 1 · 30 V , E Q u i n h y d r o n e will be
Options
- A1 · 36   V
- B1 · 32 V
- C1 · 42 V
- D1 · 26 V
Correct answer
C. 1 · 42 V
Step-by-step solution
E = E 0 - 0.059 2 l o g H + 2 = 1 · 30 - 0.059 2 l o g 10 - 2 2 = 1 · 30 + 0.236 2 = 1 · 418 V