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Calculate the equilibrium constant for the reaction (in 10 12 ) Fe 2 + + Ce 4 + ⇌ Fe 3 + + Ce 3 + Given, E o Ce 4 + / Ce 3 + = 1.44 V, E o Fe 3 + / Fe 2 + = 0.68 V RT F = . 0591

Correct answer

7.07

Step-by-step solution

Fe 2 + + Ce 4 + ⇌ Fe 3 + + Ce 3 + E o = E o Ce 4 + / Ce 3 + - E o Fe 3 + / Fe 2 + = 1.44 - 0.68 = 0.76 V ∵ E o = 0.059 log K ⇒ log K = E o 0.0592 = 0.76 0.059 = 12.85 ⇒ K = 7.07 × 10 1 2

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