NTA Abhyas JEE Main2020ChemistryElectrochemistryPractice
Calculate value of E ° C e 4 + / C e 3 + . If E ° c e l l for the cell reaction, 2 C e 4 + + C o → 2 C e 3 + + C o 2 + is 1.89 V. If E ° C o / C o 2 + = - 0.28 V
Options
- A– 1.64 V
- B+ 1.64 V
- C– 2.08 V
- D+ 2.17 V
Correct answer
B. + 1.64 V
Step-by-step solution
In this cell C o is oxidised and it acts as anode and Ce acts as cathode. E C e l l 0 = E C a t h o d e 0 - E A n o d e 0 = 1.89 = E C e l l 0 - ( - 0.28 ) E C e l l 0 = 1.89 - 0.28 = 1.61 Volts.