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A fuel cell involves combustion of the butane at at 1 atm and 298 K C 4 H 10 g + 13 2 O 2 g → 4 CO 2 g + 5 H 2 O l Δ G ° = - 2744 kJ/mole The value of E c e l l o Report your answer by rounding it upto nearest whole number.

Correct answer

1

Step-by-step solution

C 4 H 10 g + 13 2 O 2 g → 4 CO 2 g + 5 H 2 O l Here total change in oxidation number of C-atoms = + 16 - ( - 10 ) = + 26 It means total number of e - involved = 26 As E c e l l o = - Δ G ° n F = - ( - 2744 ) × 1000 26 × 96500 = + 1.09 V ≈ 1.0 V

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