The measured voltage of the cell, Pt (s) H 2 1.0 atm H + (q) | Ag + 1.0 M Ag (s) is 1.02 V at.298 K and E c e l l o is 0.80 V, Find the pH of the solution. Report your answer by rounding it upto nearest whole number.

Step-by-step solution

E cell = E cell o − 0 .059 n log [H + ] 2 [Ag + ] 2 = E cell o − 0 .059 × 2 2 log H + Ag + E cell o − 0.059 × 2 log H + 1 = E cell o + 0.059 ( − log[H + ] ) 1 = E cell o + 0.059 pH So pH = E cell − E cell o 0 .059 = 1 .02 − 0 .80 0 .059 = 3 .728