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Given E Cr 3 + / Cr 0 = - 0 . 7 4 V; E MnO 4 - / Mn 2 + 0 = 1 . 5 1 V E ⁡ C r 2 O 7 2 - / C r 3 + 0 = 1 . 3 3 V ; E ⁡ Cl 2 / Cl - 1 0 = 1 . 3 6 V Based on the data given above,strongest oxidising agent will be :

Options

  1. AMn 2 +
  2. BMnO 4 -
  3. CCl -
  4. DCr 3 +

Correct answer

B. MnO 4 -

Step-by-step solution

Strongest oxidising agent has the highest standard reduction potential MnO 4 - / Mn 2 + = 1 . 5 1 V

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