NTA Abhyas JEE Main2020ChemistryIonic EquilibriumPractice
20 m l of 0.1 M N a O H is added to 30 ml 0.1 M NaOH 30 ml 0.2 M CH 3 COOH pK a = 4.74 , calculate the pH of the resulting solution? [given: log 2 = 0.3 ]
Options
- A3.44
- B4.01
- C4.44
- D4.71
Correct answer
C. 4.44
Step-by-step solution
N a O H + C H 3 C O O H → C H 3 C O O N a + H 2 O m m o l 2 6 L R - 4 2 The resulting solution is an acidic buffer. so pH = pK a + log Salt Acid = 4.71 + log 2 4 = 4.44