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NTA Abhyas 2020
Exam
NTA Abhyas
Year
2020
Subject
Chemistry
Chapter
Redox Reactions

NTA Abhyas 2020 · Chemistry · Redox Reactions

One mole of N _ 2 H _ 4 looses ten moles of electrons to form a new...

One mole of N2H4{N}_{2}{H}_{4} looses ten moles of electrons to form a new compound Y. Assuming that all the nitrogen appears in the new compound, what is the oxidation state of nitrogen in Y? (there is no change in the oxidation state of hydrogen)

Options

  1. A+2
  2. B-2
  3. C+3
  4. D+4

Correct answer

C. +3

Step-by-step solution

N2H4→Y+10e−{N}_{2}{H}_{4} \to Y + 10e^{-}
Oxidation state of N in N2H4{N}_{2}{H}_{4} :
2X+4=02X + 4 = 0
X=−2X = - 2
The two, nitrogen atoms will balance the charge of 10e−110e^{- 1}.
So, oxidation state of N will increase by +5, that is., from -2 to +3.
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