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The combustion of sodium in excess air yields a higher oxide. What is the oxidation state of the oxygen in the product? Neglect the negative sign.

Correct answer

1

Step-by-step solution

Na + O 2 → Na 2 O , Na 2 O + 1 2 O 2 → Na 2 O 2 It exists as 2 Na + and O 2 2 − So oxidation state of O is − 1

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