K M n O 4 reacts with KI , in basic medium to form I 2 and M n O 2 . When 250 mL of 0.1 M K I solution is mtextxed with 250 mL of 0.02 M K M n O 4 in basic medium, what is the number of moles of I 2 formed?

Step-by-step solution

Number of mtextlli equivalents of M n O 4 - = 0.02 × 3 × 250 = 15 Number of mtextlli equivalents of l 2 = 0.1 × 1 × 250 = 25 Thus, here M n O 4 - is limtextting reagent. ∴ Number of mtextlli equivalents of l 2 formed = Number of mtextlli equivalent of M n O 4 - = 15 Or number of equivalent of l 2 formed = 15 1000 = 0.015 ∴ Number of moles of l 2 formed = 0.015 2 = 0.0075