NTA Abhyas JEE Main2020ChemistryRedox ReactionsPractice
Product (X and Y) of the following reactions (1 and 2) are (1) 2 N a O H ( Cold and dilute ) + C l 2 → N a C l + X + H 2 O (2) 6 N a O H ( H o t and conc. ) + 3 C l 2 → N a C l + Y + 3 H 2 O
Options
- AX = N a C l O 3 and Y = N a O C l
- BX = N a O C l and Y = N a C l O 3
- CX = N a H C l O 3 and Y = N a O C l
- DX = N a C l O 3 and Y = N a H C l O 3
Correct answer
B. X = N a O C l and Y = N a C l O 3
Step-by-step solution
C l 2 + 2 N a O H ( d i l . ) → c o l d N a C l + N a O C l ( X ) + H 2 O 3 C l 2 + 6 N a O H ( c o n c . ) → h o t 5 N a C l + N a C l O 3 ( Y ) + 3 H 2 O