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Calculate the amount of calcium oxide (in grams) required when it reacts with 852 g of P 4 O 10 .

Correct answer

1008

Step-by-step solution

6 CaO + P 4 O 1 0 ⟶ 2 Ca 3 PO 4 2 1 Mole P 4 O 10 = 284 g/mole Moles of P 4 O 10 = 8 5 2 2 8 4 = 3 moles Moles of CaO = 18 moles Mass of CaO = 18 x 56 = 1008 g

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