NTA Abhyas JEE Main2020ChemistryStructure of AtomPractice
What electronic transition in L i 2 + produces the radiation of same wavelength as the first line in the Balmer's series of Hydrogen spectrum-
Options
- An 2 = 3 to n 1 = 2
- Bn 2 = 6 to n 1 = 3
- Cn 2 = 9 to n 1 = 6
- Dn 2 = 9 to n 1 = 8
Correct answer
C. n 2 = 9 to n 1 = 6
Step-by-step solution
First line in balmer series means transition from n = 3 to n = 2 . Now, 9 t h orbit of L i 2 + has same energy as third orbit of ′ H ′ atom & 6 t h orbit of L i 2 + has same energy as second orbit of ′ H ′ atom. So n = 9 to n = 6 transition in L i 2 + would have same wavelength as first line in balmer series of H -spectrum.