NTA Abhyas JEE Main2020ChemistryStructure of AtomPractice
The energy of second Bohr orbit of the hydrogen atom is − 328 kJ mol − 1 The energy of fourth Bohr orbit would be:
Options
- A− 41 kJ mol − 1
- B− 82 kJ mol − 1
- C− 164 kJ mol − 1
- D− 1312 kJ mol − 1
Correct answer
B. − 82 kJ mol − 1
Step-by-step solution
We know that E n   =   E 1   ×   Z n 2 Given E 2   =   E 1 2 2   =   − 328 kJ mol − 1 E 4   =   E 2 2 2   =   − 328 4   kJ mol − 1   =   − 82 kJ mol − 1