NTA Abhyas JEE Main2020ChemistryStructure of AtomPractice

Radiation corresponding to the transition n = 4 to n = 2 in hydrogen atoms falls on a certain metal (work function = 2.0 e V ). The maximum kinetic energy of the photoelectrons will be:

Options

A0.55 e V
B2.55 e V
C4.45 e V
DNone

Correct answer

A. 0.55 e V

Step-by-step solution

E n = - 13.6 n 2 e V ; E 2 = - 13.6 2 2 ; E 4 = - 13.6 4 2 e V / a t o m Δ E = E 4 - E 2 = 2.55 e V Absorbed energy = work function of metal + KE 2.55 = 2 + K . E . K . E . = 0.55 e V

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