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NTA Abhyas JEE Main2020ChemistryStructure of AtomPractice

Ionisation energy of a hydrogen like species is 54 .4 eV . Calculate radius of second bohr orbit of this species.

Options

  1. A0.529     A o
  2. B1.058     A o
  3. C2.116     A o
  4. D2.116     A o

Correct answer

B. 1.058     A o

Step-by-step solution

Ionisation energy 13.6 × z 2 = 54.4 ∴   Z   =   2 r   =   0 .529   n 2 z A o   =   0 .529   ×   2 2 2   =   1 .058   A o

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