NTA Abhyas JEE Main2020ChemistryStructure of AtomPractice
The angular momentum of an electron in H e + moving in an orbit is h / π . The de-brogile wavelength associated with electron is: [ a 0 is radius of first bohr's orbit of H -atom]
Options
- A2 π a 0
- Bπ a 0
- C4 π a 0
- Dπ a 0 2
Correct answer
A. 2 π a 0
Step-by-step solution
n h 2 π = h π n = 2 r = a 0 × n 2 z = a 0 × 2 2 2 = 2 a 0 n λ = 2 π r λ = π r = π 2 a 0