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NTA Abhyas JEE Main2020ChemistryStructure of AtomPractice

The ratio of minimum to maximum wavelengths in Balmer series of H -atom is

Options

  1. A5 : 9
  2. B5 : 36
  3. C1 : 4
  4. D3 : 4

Correct answer

A. 5 : 9

Step-by-step solution

We know that 1 λ m i n = R 1 4 - 1 ∞ = R 4 1 λ m a x = R 1 4 - 1 9 = 5 R 36 ⇒ λ m i n λ m a x = 4 R 36 5 R = 5 9

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