NTA Abhyas JEE Main2020ChemistryStructure of AtomPractice
The angular momentum of electron in L i 2 + is found to be 14 h 11 . Calculated the potential energy (in eV) of system.
Options
- A13.6 × 3 8 2
- B- 13.6 × 3 8 2
- C- 2 × 13.6 × 3 8 2
- D- 2 × 13.6 × 8 3 2
Correct answer
C. - 2 × 13.6 × 3 8 2
Step-by-step solution
The angular momentum of an electron in an n t h orbit is given by m e vr = n ⋅ h 2π ; n = 1.2.3....... n h 2 π = 14 h 11 ⇒ n = 8 P . E = - 2 × 13.6 Z 2 n 2 e V Potential energy = - 2 × 13.6 × Z n 2 Potential energy = - 2 × 13.6 × 3 8 2 ∵ f o r L i 2 + , Z = 3