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In ψ 321 , the sum of angular momentum, spherical nodes and angular node is

Options

  1. A6 h + 4 π 2 π
  2. B6 h 2 π + 3
  3. C6 h + 2 π 2 π
  4. D6 h + 8 π 2 π

Correct answer

A. 6 h + 4 π 2 π

Step-by-step solution

ψ 321 : n = 1 , l = 2 , m = 1 Angular momentum = h 2 π l ( l + 1 ) = 6 h 2 π Spherical nodes = 3 - 2 - 1 = 0 ; Angular node = 2 Sum of all the above = 6 h 2 π + 2 = 6 h + 4 π 2 π

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