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A certain metal when irradiated by light r = 3.2 × 10 16 H z emtextts photoelectrons with twice kinetic energy as did photoelectrons when the same metal is irradiated by light r = 2.0 × 10 16 H z . Then v 0 of metal is

Options

  1. A1.2 × 10 14 H z
  2. B8 × 10 15 H z
  3. C1.2 × 10 16 H z
  4. D4 × 10 12 H z

Correct answer

B. 8 × 10 15 H z

Step-by-step solution

K E 1 = h v 1 - h v 0 K E 2 = h v 2 - h v 0 As, K E 1 = 2 × K E 2 ∴ h v 1 - h v 0 = 2 h v 2 - h v 0 Or, h v 0 = 2 h v 2 - h v 1 Or , v 0 = 2 v 1 - v 1 = 2 × 2 × 10 16 - 3.2 × 10 16 = 0.8 × 10 16 H z = 8 × 10 15 H z

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