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NTA Abhyas JEE Main2020ChemistryStructure of AtomPractice

The wavelength of the third line of the Balmer series for a hydrogen atom is

Options

  1. A21 100 R H
  2. B100 21 R H
  3. C21 R H 100 R
  4. D100 R H 21

Correct answer

B. 100 21 R H

Step-by-step solution

1 λ = R H 1 n 1 2 - 1 n 2 2 for the H-atom For the Balmer series, n 1 = 2 and n 2 = 5 (for the third line). 1 λ = R H 1 2 2 - 1 5 2 = 21 100 R H So λ = 100 21R H

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