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NTA Abhyas JEE Main2020ChemistryStructure of AtomPractice

The energy of an electron in the first orbit of H - atom is - 13.6 e V . The possible energy values of the excited state for electrons in Bohr orbits of L i 2 + ions is/are-

Options

  1. A– 3.0 e V
  2. B– 30.6 e V
  3. C– 13.6 e V
  4. DBoth B & C are correct

Correct answer

D. Both B & C are correct

Step-by-step solution

E n = – 13.6 Z 2 n 2 for L i 2 + , E n = – 13.6 × 9 n 2 = - 122.4 n 2 e V If n = 1 , E n = – 122.4 e V If n = 2 , E n = – 30.6 e V If n = 3 , E n = – 13.6 e V

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