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The wave number of the first emission line in the Balmer series of H-Spectrum is n 36 R . The value of 'n' is. (R = Rydberg constant):

Correct answer

5

Step-by-step solution

v ¯ = R Z 2 1 2 2 - 1 3 2 = R 1 4 - 1 9 = 5 R 36 = n 36 R Hence n = 5.

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