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When a transition of electron in H e + takes place from n 2 to n 1 then wave number in terms of Rydberg constant R will be (Given n 1 + n 2 = 4 , n 2 - n 1 = 2 )

Options

  1. A3 R 4
  2. B8 R 9
  3. C32 R 9
  4. D24 R 9

Correct answer

C. 32 R 9

Step-by-step solution

n 1 + n 2 = 4 n 2 − n 1 = 2 2 n 2 = 6 n 2 = 3 n 1 = 1 3 → 1 ν ̄ = 1 λ = R Z 2 1 n 1 2 - 1 n 2 2 = R × 2 2 1 1 2 - 1 3 2 = 4 R × 8 9 = 32 R 9

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