NTA Abhyas JEE Main2020ChemistryStructure of AtomPractice
If λ = c 2 n 2 n 2 - 2 2 for Balmer series, what is the value of c 2 ?
Options
- A4 R H
- B2 R H
- C2 R H
- D4 R H
Correct answer
A. 4 R H
Step-by-step solution
λ = c 2 n 2 n 2 - 2 2 or 1 λ = 1 c 2 n 2 - 2 2 n 2 = 1 c 2 1 - 2 2 n 2 = 2 2 c 2 1 2 2 - 1 n 2 So, R H = 2 2 c 2 or c 2 = 4 R H