The atomic structure of H e + arises due to transition from n 2 to n 1 level. If n 1 + n 2 is 3 and n 2 - n 1 is 1. Find the λ in nm of transition for this series in H e + in nm.

Step-by-step solution

n 1 + n 2 = 3 …(i) n 2 - n 1 = 1 …(ii) 2 n 2 = 4 So n 2 = 2 Putting the value of n 2 in (i) n 1 = 3 - n 2 = 3 - 2 = 1 1 λ = R z 2 1 n 1 2 - 1 n 2 2 = R . 2 2 1 1 2 - 1 2 2 λ = 1 3 R = 1 3 × 109678 c m - 1 = 3 × 1 0 - 6 c m = 3 × 1 0 - 6 × 1 0 7 = 30 nm.