Given that r n − 1   +   r n   =   r n   +   1 where r represents Bohr's orbit for (n − 1) th ,   n th and (n   +   1) th orbit, then n is

Step-by-step solution

r n   −   1   +   r n   =   r n   +   1 and r n   =   n 2   r 1 i .e .,   (n − 1) 2 r 1   +   n 2   r 1   =   (n   +   1) 2   r 1 ⇒ (n − 1) 2   +   n 2   =   (n   +   1) 2 ⇒ n 2 − 2n   +   1   +   n 2 =   n 2   +   2n   +   1 &#x21D2