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NTA Abhyas JEE Main2020ChemistryStructure of AtomPractice

I E 1 for H and He are 13.6 eV and 24.6 eV respectively. Thus, energy required in eV during the formation of He 2+ by He → He 2+ + 2e − is

Correct answer

79

Step-by-step solution

H → H + + e − ; 13 .6 eV IE 2 of He = 1 E 1 of He + = E 1 H × Z 2 = 13 .6 × 4 = 54 .4 eV He + → He 2 + ; 54.4 eV So, He → He 2+ ; 54 .4 eV + 24 .6 eV = 79.0 eV

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