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In H e ⊕ ion sample e - is in ground state, if photon of energy 52.24 e V is given to the sample all the atom goes to higher energy state. It again falls back up to ground state. If it is not emitting any lines in Balmer series then what is the maximum possible number of spectral lines observed

Correct answer

6

Step-by-step solution

13 .6 × 2 2 1 − 1 n 2 = 52 .24 ⇒ 13 .6 − 13 .6 n 2 = 13 .06 ⇒ 13 .6 n 2 = 0 .54 ⇒ n = 5 Total line = 5 5 − 1 2 = 10 But it is not emitting balmer lines hence ⇒ total line = 10 - 3 = 7 But it will also bit enquit 2 → 1 line Hence total line = 7 - 1 = 6

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