NTA Abhyas JEE Main2020ChemistryStructure of AtomPractice
The first orbital of H is represented by ψ = 1 π 1 a 0 e - r / a 0 , where a 0 is Bohr's radius. The probability of finding the electron at a distance r, from the nucleus in the region dV is
Options
- Aψ 2 d r
- B∫ ψ 2 4 π r 2 d v
- Cψ 2 4 π r 2 d r
- D∫ ψ d v
Correct answer
C. ψ 2 4 π r 2 d r
Step-by-step solution
This can be obtained by the solution of Schrodinger wave equation as follows Probability = ψ 2 d V As orbital is spherically symmetrical So V = 4 3 π r 3 i.e., d V d r = 4 π r 2 Hence, probability = ψ 2 4 π r 2 d r .