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The wave number of first emission line in the atomic spectrum of hydrogen in the Balmer series is

Options

  1. A5 R 36 c m - 1
  2. B3 R 4 c m - 1
  3. C7 R 144 c m - 1
  4. D9 R 400 c m - 1

Correct answer

A. 5 R 36 c m - 1

Step-by-step solution

Balmer series starts from n = 2 . So first emission line in atomic spectrum of H is 2 → 3 1 λ = RZ 2 1 n 1 2 − 1 n 2 2 ν - = R 1 2 2 - 1 3 2 c m - 1 = 5 R 36 c m - 1

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