Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
NTA Abhyas 2020
Exam
NTA Abhyas
Year
2020
Subject
Mathematics
Chapter
Area Under Curves

NTA Abhyas 2020 · Mathematics · Area Under Curves

The area bounded by the curves y = x , y = |x| , y = | x| and y = |...

The area bounded by the curves y = \text\ln x \text{,} y = \text\ln \left|x\right| \text{,} y = \left|\text\ln x\right| and y = \left|\text\ln \left|x\right|\right|, for x∈(−1,1)x \in ( - 1, 1 ) isThe area bounded by the curves y = x , y = |x| , y = | x| and y = | |x|| , for x ∈ ( - 1, 1 ) is

Correct answer

4

Step-by-step solution

The required shaded region is as shown in figure

The area bounded by the curves y = x , y = |x| , y = | x| and y = | |x|| , for x ∈ ( - 1, 1 ) is

As the graph is symmetric in all quadrants, we calculate area in one quadrant and multiply by 4.

Hence, required area =4∣∫01(ln⁡x).dx∣= 4| \mathop{∫}_{0}^{1} ( \ln x ) . dx |

A=4∣[xlnx−x]01∣A = 4| {[ xlnx - x ]}_{0}^{1} |

A=4∣[(1ln⁡1−1)−lim⁡x→0+(xlnx−x)]∣A = 4| [ ( 1\ln 1 - 1 ) - \lim_{x \to {0}^{+}} ( xlnx - x ) ] |

A=4∣[(0−1)−lim⁡x→0+ln⁡x1x−0]∣=4∣[−1−lim⁡x→0+1x−1x2]∣A = 4| [ ( 0 - 1 ) - \lim_{x \to {0}^{+}} \dfrac{\ln x}{\dfrac{1}{x}} - 0 ] | = 4| [ - 1 - \lim_{x \to {0}^{+}} \dfrac{\dfrac{1}{x}}{- \dfrac{1}{{x}^{2}}} ] |

A=4∣[−1+lim⁡x→0+x]∣A = 4| [ - 1 + \lim_{x \to {0}^{+}} x ] |

A=+4∣−1∣A = + 4| - 1 |

A=4A = 4
Practice Area Under Curves on Quantrex Academy →

More from Area Under Curves

Passage: Consider the curve C_1 given by y = e^ -x for x ∈ [0, 10π] , and the curve C_2… JEE Advanced 2026Passage: Consider the ellipses given by x^2 + 4y^2 = 1 and 4x^2 + y^2 = 1 . Question: If… JEE Advanced 2026The area of the region \ (x, y) : x^2 - 8x ≤ y ≤ -x\ is : JEE Main 2026The area of the region \ (x, y) : 0 ≤ y ≤ 6 - x, y^2 ≥ 4x - 3, x ≥ 0\ is: JEE Main 2026The area of the region R = \ (x, y): xy ≤ 27, 1 ≤ y ≤ x^2\ is equal to: JEE Main 2026The area of the region bounded by the curves x+3y^2=0 and x+4y^2=1 is equal to: JEE Main 2026The area of the region \ (x, y): y ≤ π - |x|, y ≤ |x x|, y ≥ 0\ is: JEE Main 2026If the area of the region bounded by 16x^2 - 9y^2 = 144 and 8x - 3y = 24 is A, then 3(A +… JEE Main 2026Let P_ 1 : y=4 x^ 2 and P_ 2 : y=x^ 2 +27 be two parabolas. If the area of the bounded… JEE Main 2026The area of the region R=\ (x, y): x y ≤ 8,1 ≤ y ≤ x^ 2 , x ≥ 0\ is JEE Main 2026Let f(α) denote the area of the region in the first quadrant bounded by x=0, x=1, y^ 2 =x… JEE Main 2026Let A_ 1 be the bounded area enclosed by the curves y=x^ 2 +2, x+y=8 and y -axis that… JEE Main 2026The area of the region enclosed between the circles x^ 2 +y^ 2 =4 and x^ 2 +(y-2)^ 2 =4… JEE Main 2026Let the area of the region bounded by the curve y= \ x, x\ , lines x=0, x=(3 π)/(2) , and… JEE Main 2026The area of the region A=\ (x, y): 4 x^ 2 +y^ 2 8. and .y^ 2 4 x\ is: JEE Main 2026Let the line x=-1 divide the area of the region \ (x, y): 1+x^ 2 ≤ y ≤ 3-x\ in the ratio… JEE Main 2026 Full Area Under Curves list Area Under Curves JEE Maths PYQsJEE Mathematics PYQs All NTA Abhyas JEE Main PYQs