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NTA Abhyas 2020
Exam
NTA Abhyas
Year
2020
Subject
Mathematics
Chapter
Area Under Curves

NTA Abhyas 2020 · Mathematics · Area Under Curves

The parabolas y^ 2 = 4x and x^ 2 = 4y divide the square region...

The parabolas y2=4xy^{2} = 4x and x2=4yx^{2} = 4y divide the square region bounded by the lines x=4x = 4, y=4y = 4 and the coordinate axes. If S1,S2,S3{S}_{1}, {S}_{2}, {S}_{3} are respectively the areas of these parts numbered from top to bottom of the square region, then S1:S2:S3{S}_{1}: {S}_{2}: {S}_{3} isThe parabolas y^ 2 = 4x and x^ 2 = 4y divide the square region bounded by the lines x = 4 , y = 4 and the coordinate

Options

  1. A2:1:22: 1: 2
  2. B1:1:11: 1: 1
  3. C1:2:11: 2: 1
  4. D1:2:31: 2: 3

Correct answer

B. 1:1:11: 1: 1

Step-by-step solution

y2=4xy^{2} = 4x and x2=4yx^{2} = 4y are symmetric about line y=xy = x

⇒⇒ Area bounded between y2=4xy^{2} = 4x and y=xy = x is ∫04(2x−x)dx=83{∫}_{0}^{4}\left(2\sqrt{x} - x\right)dx = \dfrac{8}{3}

The parabolas y^ 2 = 4x and x^ 2 = 4y divide the square region bounded by the lines x = 4 , y = 4 and the coordinate

⇒AS2=163⇒ {A}_{{S}_{2}}= \dfrac{16}{3} and AS1=AS3=163Area of rectangle−S22{A}_{S1} = {A}_{S3} = \dfrac{16}{3} { \dfrac{\text{Area of rectangle} - {S}_{2}}{2} }

⇒AS1:AS2:AS2::1:1:1⇒{A}_{{S}_{1}}: {A}_{{S}_{2}}: {A}_{{S}_{2}}: : 1: 1: 1.
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