Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
NTA Abhyas 2020
Exam
NTA Abhyas
Year
2020
Subject
Mathematics
Chapter
Area Under Curves

NTA Abhyas 2020 · Mathematics · Area Under Curves

The area (in sq. units) bounded by the curve f(x) = \ cases e^ -...

The area (in sq. units) bounded by the curve f\left(x\right) = \left\{\begin{cases}e^{- \left|x\right|} & \left|x\right| ≥ 1 \\ \left|x\right| - 1 + \dfrac{1}{e}& \left|x\right| < 1\end{cases}\right) and thex$-axis isThe area (in sq. units) bounded by the curve f(x) = \ cases e^ - |x| & |x| ≥ 1 |x| - 1 + (1)/(e)& |x| < 1 cases ) and

Options

  1. A2+2e22 + \dfrac{2}{e^{2}}
  2. B2+1e22 + \dfrac{1}{e^{2}}
  3. C1e2\dfrac{1}{e^{2}}
  4. D1+2e21 + \dfrac{2}{e^{2}}

Correct answer

D. 1+2e21 + \dfrac{2}{e^{2}}

Step-by-step solution

The area (in sq. units) bounded by the curve f(x) = \ cases e^ - |x| & |x| ≥ 1 |x| - 1 + (1)/(e)& |x| < 1 cases ) and
∵∵ Graph of f(x)f \left(x\right) is symmetric about xx-axis, hence,
Area =2∫= 2\mathop{∫}_{0}^{\iinfty}\left|f\left(x\right)\right|dx
= 2\left[\dfrac{1}{2} \times \left(1 - \dfrac{1}{e}\right)\left(1 - \dfrac{1}{e}\right) + \dfrac{1}{2} \times \dfrac{1}{e} \times \dfrac{1}{e} +∫1∞\mathop{∫}_{1}^{\infty} e^{- x}dx\right]<br/><br />= 2\left[12[1−2e+2e2]+[−e−x]\dfrac{1}{2} \left[1 - \dfrac{2}{e} + \dfrac{2}{e^{2}}\right] + {\left[- e^{- x}\right]}_{1}^{\infty}\right]<br/><br />=\left[1 - \dfrac{2}{e} + \dfrac{2}{e^{2}} + \dfrac{2}{e}\right] =1 + \dfrac{2}{e^{2}}& sq. units
Practice Area Under Curves on Quantrex Academy →

More from Area Under Curves

Passage: Consider the curve C_1 given by y = e^ -x for x ∈ [0, 10π] , and the curve C_2… JEE Advanced 2026Passage: Consider the ellipses given by x^2 + 4y^2 = 1 and 4x^2 + y^2 = 1 . Question: If… JEE Advanced 2026The area of the region \ (x, y) : x^2 - 8x ≤ y ≤ -x\ is : JEE Main 2026The area of the region \ (x, y) : 0 ≤ y ≤ 6 - x, y^2 ≥ 4x - 3, x ≥ 0\ is: JEE Main 2026The area of the region R = \ (x, y): xy ≤ 27, 1 ≤ y ≤ x^2\ is equal to: JEE Main 2026The area of the region bounded by the curves x+3y^2=0 and x+4y^2=1 is equal to: JEE Main 2026The area of the region \ (x, y): y ≤ π - |x|, y ≤ |x x|, y ≥ 0\ is: JEE Main 2026If the area of the region bounded by 16x^2 - 9y^2 = 144 and 8x - 3y = 24 is A, then 3(A +… JEE Main 2026Let P_ 1 : y=4 x^ 2 and P_ 2 : y=x^ 2 +27 be two parabolas. If the area of the bounded… JEE Main 2026The area of the region R=\ (x, y): x y ≤ 8,1 ≤ y ≤ x^ 2 , x ≥ 0\ is JEE Main 2026Let f(α) denote the area of the region in the first quadrant bounded by x=0, x=1, y^ 2 =x… JEE Main 2026Let A_ 1 be the bounded area enclosed by the curves y=x^ 2 +2, x+y=8 and y -axis that… JEE Main 2026The area of the region enclosed between the circles x^ 2 +y^ 2 =4 and x^ 2 +(y-2)^ 2 =4… JEE Main 2026Let the area of the region bounded by the curve y= \ x, x\ , lines x=0, x=(3 π)/(2) , and… JEE Main 2026The area of the region A=\ (x, y): 4 x^ 2 +y^ 2 8. and .y^ 2 4 x\ is: JEE Main 2026Let the line x=-1 divide the area of the region \ (x, y): 1+x^ 2 ≤ y ≤ 3-x\ in the ratio… JEE Main 2026 Full Area Under Curves list Area Under Curves JEE Maths PYQsJEE Mathematics PYQs All NTA Abhyas JEE Main PYQs