NTA Abhyas JEE Main2020MathematicsDefinite IntegrationPractice
Let I = ∫ 0 1 sin x x d x a n d J = ∫ 0 1 cos x x d x . Then, which one of the following is true?
Options
- AI > 2 3 a n d J < 2
- BI > 2 3 a n d J > 2
- CI < 2 3 a n d J < 2
- DI < 2 3 a n d J > 2
Correct answer
C. I < 2 3 a n d J < 2
Step-by-step solution
Since, I = ∫ 0 1 sin ⁡ x x d x < ∫ 0 1 x x d x as in x ∈ 0,1 ,   x > sin ⁡ x I < ∫ 0 1 x d x = 2 3 x 3 / 2 0 1 ⇒ I < 2 3 For, x ∈ 0,1 ,   cos ⁡ x x < 1 x Hence, J = ∫ 0 1 cos ⁡ x x d x < ∫ 0 1 x - 1 2 d x = 2 ⇒ J < 2