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NTA Abhyas JEE Main2020MathematicsDefinite IntegrationPractice

The value of the integral I = ∫ 1 2 t t + t 1 + ln t d t is equal to ( . and . denotes the greatest integer and fractional part function respectively)

Options

  1. A0
  2. B1
  3. C2
  4. D3

Correct answer

D. 3

Step-by-step solution

As t = 0 , we get, I = ∫ 1 2 t t 1 + ln ⁡ t d t = ∫ 1 2 d t t = t t 1 2 = 2 2 – 1 1 = 3

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