NTA Abhyas JEE Main2020MathematicsDefinite IntegrationPractice
Let Ι 1 = ∫ 0 1 e x 2 d x and Ι 2 = ∫ 0 1 2 x 2 e x 2 d x , then the value of Ι 1 + Ι 2 is equal to
Options
- A1
- B2
- Ce
- De 2
Correct answer
C. e
Step-by-step solution
Ι 2 = ∫ 0 1 2 x 2 e x 2 d x = ∫ 0 1 2 x e x 2 x d x Using integration by parts, Ι 2 = x e x 2 0 1 - ∫ 0 1 e x 2 d x Ι 2 + Ι 1 = e