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NTA Abhyas JEE Main2020MathematicsDefinite IntegrationPractice

The value of ∫ - 1 1 c o t - 1 x + x 3 + x 5 x 4 + x 2 + 1 d x is equal to

Options

  1. Aπ 2
  2. Bπ 4
  3. C3 π 4
  4. Dπ

Correct answer

D. π

Step-by-step solution

x + x 3 + x 5 x 4 + x 2 + 1 is an odd function, let it be equal to λ , So, Ι s a y = ∫ 0 1 c o t - 1 ( λ ) + c o t - 1 - λ d x = π ∫ 0 1 d x = π

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