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Consider A = ∫ 0 π 4 s i n 2 x x d x , then

Options

  1. AA > π 2
  2. BA = π 2
  3. CA < π 2
  4. DA > π

Correct answer

C. A < π 2

Step-by-step solution

As s i n &#952; &#60; &#952; , &#160; &#8704; &#952; &#8712; 0 , &#960; 2 &#8756; s i n 2 x &#60; 2 x So, A = 2 &#8747; 0 &#960; 4 s i n 2 x 2 x d x &#60; 2 &#8747; 0 &#960; 4 1 d x &#8658; A &#60; 2 &#960; 4 = &#960; 2

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