NTA Abhyas JEE Main2020MathematicsDefinite IntegrationPractice
The value of ∫ - π π 2 cos x 1 + e x d x is equal to
Options
- Aπ 2
- Bπ
- C0
- D2 π
Correct answer
C. 0
Step-by-step solution
Let, Ι = ∫ - π π 2 cos ⁡ x 1 + e x d x Ι = ∫ 0 π 2 cos ⁡ x 1 + e x + 2 cos ⁡ x 1 + e - x d x Ι = ∫ 0 π 2 cos ⁡ x 1 1 + e x + e x 1 + e x d x Ι = ∫ 0 π 2 cos ⁡ x d x Ι = 0