NTA Abhyas JEE Main2020MathematicsDefinite IntegrationPractice
The value of the definite integral Ι = ∫ - 1 1 ln 2 - s i n 3 x 2 + s i n 3 x d x is equal to
Options
- Aln 4
- Bln 2
- C0
- Dln 1 2
Correct answer
C. 0
Step-by-step solution
Let, ln ⁡ 2 - s i n 3 x 2 + s i n 3 x = f x Then, f - x = ln ⁡ 2 + s i n 3 x 2 - s i n 3 x = - ln ⁡ 2 - s i n 3 x 2 + s i n 3 x = - f x Hence, ∫ - 1 1 f x d x = 0