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The value of ∫ 0 2 x 2 - 2 x + 4 s i n x - 1 2 x 2 - 4 x + 5 d x is equal to

Correct answer

0

Step-by-step solution

Let, Ι = ∫ 0 2 x 2 - 2 x + 4 s i n x - 1 d x 2 x 2 - 2 x + 5 ∫ 0 2 x - 1 2 + 3 s i n x - 1 2 x - 1 2 + 3 d x Put x - 1 = t , d x = d t I = ∫ - 1 1 t 2 + 3 2 t 2 + 3 sin ⁡ t d t = 0 Since, this is an odd function

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