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NTA Abhyas JEE Main2020MathematicsDefinite IntegrationPractice

The value of the integral Ι = ∫ 0 π 2 cos ⁡ x - sin ⁡ x 10 - x 2 + π x 2 d x is equal to

Options

  1. Aπ 2
  2. Bπ
  3. C0
  4. D4 π

Correct answer

C. 0

Step-by-step solution

Applying a + b - x , property, Ι = ∫ 0 π 2 sin ⁡ x - cos ⁡ x 10 + π 2 - x x d x ⇒ Ι = - Ι ⇒ 2 Ι = 0 ⇒ Ι = 0

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