NTA Abhyas JEE Main2020MathematicsDefinite IntegrationPractice
The integral I = ∫ π 4 π 2 sin 6 x d x satisfies
Options
- AI > π 2
- BI > π 4
- CI ∈ π 4 , π 2
- DI ∈ π 32 , π 4
Correct answer
D. I ∈ π 32 , π 4
Step-by-step solution
∫ π 4 π 2 sin 6 π 4 d x < ∫ π 4 π 2 sin 6 x d x < ∫ π 4 π 2 sin 6 π 2 d x ⇒ 1 8 ∫ π 4 π 2 d x < I < ∫ π 4 π 2 d x ⇒ 1 8 ⋅ π 4 < I < π 4 or I ∈ π 32 , π 4