If the integral ∫ 0 2 d x sin ⁡ x + sin ⁡ ( 2 - x ) = A , then the integral β = ∫ 0 2 x d x sin x + sin ( 2 - x ) is equal to

Step-by-step solution

Applying a + b + x property in β , we get β = ∫ 0 2 2 - x sin ⁡ 2 - x + sin ⁡ x d x Adding both, we get 2 β = ∫ 0 2 2 sin ⁡ x + s i n 2 - x d x ⇒ β = A